Edit:
A={0}
Under addition:
Commutative: 0+0 = 0 = 0+0
Associative: 0 + (0+0) = 0 = (0+0) + 0
Distributive: 0*(0 + 0) = 0*0 + 0*0
Closed: For all a,b such that a,b are elements of A, a + b is an element of A.
The curse.. is that it contains only 1 element?
A={0}
Under addition:
Commutative: 0+0 = 0 = 0+0
Associative: 0 + (0+0) = 0 = (0+0) + 0
Distributive: 0*(0 + 0) = 0*0 + 0*0
Closed: For all a,b such that a,b are elements of A, a + b is an element of A.
The curse.. is that it contains only 1 element?
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