Sorry for not replying for two days, but I've been trying to test Silva's way of solving this problem.
I realized that there were over five addresses that look exactly identical to the code Silva posted in his first reply:
Do I have to change every one of those five addresses and jump to five different addresses in the bottom of the program? If not, which one do I change?
Please Respond
~Solomon Leung
I realized that there were over five addresses that look exactly identical to the code Silva posted in his first reply:
Code:
0042E091 . B9 01000000 MOV ECX,1
0042E096 > 8B16 MOV EDX,DWORD PTR DS:[ESI]
0042E098 . 83BA F8060000 >CMP DWORD PTR DS:[EDX+6F8],0
0042E09F . 75 14 JNZ SHORT lf2_load.0042E0B5
0042E0A1 . 85C9 TEST ECX,ECX
0042E0A3 . 75 10 JNZ SHORT lf2_load.0042E0B5
0042E0A5 . 83BA F4060000 >CMP DWORD PTR DS:[EDX+6F4],1E
0042E0AC . 7D 07 JGE SHORT lf2_load.0042E0B5
0042E0AE . 8944BC 44 MOV DWORD PTR SS:[ESP+EDI*4+44],EAXDo I have to change every one of those five addresses and jump to five different addresses in the bottom of the program? If not, which one do I change?
Please Respond
~Solomon Leung
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