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'Random' Feature Manipulation
#5
Sorry for not replying for two days, but I've been trying to test Silva's way of solving this problem.

I realized that there were over five addresses that look exactly identical to the code Silva posted in his first reply:

Code:
0042E091   . B9 01000000    MOV ECX,1
0042E096   > 8B16           MOV EDX,DWORD PTR DS:[ESI]
0042E098   . 83BA F8060000 >CMP DWORD PTR DS:[EDX+6F8],0
0042E09F   . 75 14          JNZ SHORT lf2_load.0042E0B5
0042E0A1   . 85C9           TEST ECX,ECX
0042E0A3   . 75 10          JNZ SHORT lf2_load.0042E0B5
0042E0A5   . 83BA F4060000 >CMP DWORD PTR DS:[EDX+6F4],1E
0042E0AC   . 7D 07          JGE SHORT lf2_load.0042E0B5
0042E0AE   . 8944BC 44      MOV DWORD PTR SS:[ESP+EDI*4+44],EAX

Do I have to change every one of those five addresses and jump to five different addresses in the bottom of the program? If not, which one do I change?

Please Respond


~Solomon Leung
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Messages In This Thread
'Random' Feature Manipulation - by 1477 - 03-22-2009, 11:16 PM
RE: 'Random' Feature Manipulation - by Boop - 03-23-2009, 05:59 PM
RE: 'Random' Feature Manipulation - by 1477 - 03-24-2009, 12:41 AM
RE: 'Random' Feature Manipulation - by Boop - 03-24-2009, 05:05 PM
RE: 'Random' Feature Manipulation - by 1477 - 03-27-2009, 02:47 AM
RE: 'Random' Feature Manipulation - by Boop - 03-28-2009, 10:52 AM
RE: 'Random' Feature Manipulation - by 1477 - 03-28-2009, 07:30 PM



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